![SOLVED: Write the following equalities in exponential form (1) log, " 81 = 4 (2) log; 7 = 1 (3) Jog " =3 (4) log3 1 =0 (5) log. 64 = -3 ( SOLVED: Write the following equalities in exponential form (1) log, " 81 = 4 (2) log; 7 = 1 (3) Jog " =3 (4) log3 1 =0 (5) log. 64 = -3 (](https://cdn.numerade.com/ask_images/3ba465bb2a704811b63eea17b93884f0.jpg)
SOLVED: Write the following equalities in exponential form (1) log, " 81 = 4 (2) log; 7 = 1 (3) Jog " =3 (4) log3 1 =0 (5) log. 64 = -3 (
![Quantitative Aptitude – Algebra - Logarithms – If p^3 = q^4 = r^5 = s^6 - | Handa Ka Funda - Online Coaching for CAT and Banking Exams Quantitative Aptitude – Algebra - Logarithms – If p^3 = q^4 = r^5 = s^6 - | Handa Ka Funda - Online Coaching for CAT and Banking Exams](http://www.handakafunda.com/wp-content/uploads/2019/07/Quantitative-Aptitude-%E2%80%93-Algebra-Logarithms-%E2%80%93-If-p%5E3-q%5E4-r%5E5-s%5E6.jpg)
Quantitative Aptitude – Algebra - Logarithms – If p^3 = q^4 = r^5 = s^6 - | Handa Ka Funda - Online Coaching for CAT and Banking Exams
![Given that Log3 = 0.4771 and log 5 = 0.6990, evaluate the following without using logarithm table or calculator. Given that Log3 = 0.4771 and log 5 = 0.6990, evaluate the following without using logarithm table or calculator.](https://www.kenyaplex.com/questions/uploads/5620191022.png)
Given that Log3 = 0.4771 and log 5 = 0.6990, evaluate the following without using logarithm table or calculator.
![EXAMPLE 4 Solve a logarithmic equation Solve log (4x – 7) = log (x + 5). 5 5 log (4x – 7) = log (x + 5) x – 7 = x x – 7 = 5 3x = 12 x = 4 Write. - ppt download EXAMPLE 4 Solve a logarithmic equation Solve log (4x – 7) = log (x + 5). 5 5 log (4x – 7) = log (x + 5) x – 7 = x x – 7 = 5 3x = 12 x = 4 Write. - ppt download](https://images.slideplayer.com/33/8253501/slides/slide_16.jpg)
EXAMPLE 4 Solve a logarithmic equation Solve log (4x – 7) = log (x + 5). 5 5 log (4x – 7) = log (x + 5) x – 7 = x x – 7 = 5 3x = 12 x = 4 Write. - ppt download
![SOLVED: 1 3 log(2x+1)+3 [log(x- 4)-log(x" x'-1)] Use the Laws of Logarithms to solve the problems 59. logs 5+ log; - X = log, 10 Yso. logio 16 log1o 2x = logio " SOLVED: 1 3 log(2x+1)+3 [log(x- 4)-log(x" x'-1)] Use the Laws of Logarithms to solve the problems 59. logs 5+ log; - X = log, 10 Yso. logio 16 log1o 2x = logio "](https://cdn.numerade.com/ask_images/0afdb28962d64cefb8f42b4b86b3af19.jpg)