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In ABC, A is acute. BD and CE are perpendicular on AC and AB respectively. Prove that AB × AE = AC × AD .
![∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC. ∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC.](https://d138zd1ktt9iqe.cloudfront.net/media/seo_landing_files/b1-1623827121.png)
∆ABC is isosceles with AB = AC = 7.5 cm and BC = 9 cm (Fig 11.26). The height AD from A to BC, is 6 cm. Find the area of ∆ABC.
![in triunghiul ABC, AD perpendiculara BC, D apartine lui BC si m unghiului C=40. Se stie ca H este - Brainly.ro in triunghiul ABC, AD perpendiculara BC, D apartine lui BC si m unghiului C=40. Se stie ca H este - Brainly.ro](https://ro-static.z-dn.net/files/d8a/bdb82f7c94f4cac9ed6f2fa5294cee81.jpg)
in triunghiul ABC, AD perpendiculara BC, D apartine lui BC si m unghiului C=40. Se stie ca H este - Brainly.ro
![In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC. If BH perpendicular to FG, prove that : ( In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC. If BH perpendicular to FG, prove that : (](https://d10lpgp6xz60nq.cloudfront.net/question-thumbnail/en_643656229.png)
In the figure given alongside, squares ABDE and AFGC are drawn on the side AB and the hypotenuse AC of the right triangle ABC. If BH perpendicular to FG, prove that : (
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In triangle ABC, let M be the midpoint of BC How would you prove that if MA = MB = MC, then ∠BAC = 90 degrees? - Quora
![In Fig. Below, Be ⊥ Ac. Ad is Any Line from a to Bc Intersecting Be in H. P, Q and R Are Respectively the Mid-points of Ah, Ab and Bc. Prove In Fig. Below, Be ⊥ Ac. Ad is Any Line from a to Bc Intersecting Be in H. P, Q and R Are Respectively the Mid-points of Ah, Ab and Bc. Prove](https://www.shaalaa.com/images/_4:05c61a48f6754d6a9f2f85a1fc8ab614.png)